How do you find the derivative for ##f(x)=sinxcosx##?
You can use the : if: ##k(x)=f(x)g(x)## ##k'(x)=f'(x)g(x)+f(x)g'(x)## In your case: ##f'(x)=cos(x)cos(x)+sin(x)(-sin(x))=## ##=cos^2(x)-sin^2(x)=cos(2x)##
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